P22_036.PDF

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36. (a) Since
q
A
=
−2Q
and
q
C
= +8Q, Eq. 22-4 leads to
F
AC
4Q
2
|(−2Q)(+8Q)|
=
.
=
4π
0
d
2
π
0
d
2
(b) After making contact with each other, both
A
and
B
have a charge of
−2Q
+ (−4Q)
2
=
−3Q
.
When
B
is grounded its charge is zero. After making contact with
C,
which has a charge of +8Q,
B
acquires a charge of [0 + (−8Q)]/2 =
−4Q,
which charge
C
has as well. Finally, we have
Q
A
=
−3Q
and
Q
B
=
Q
C
=
−4Q.
Therefore,
F
AC
(c) We also obtain
F
BC
=
4Q
2
|(−4Q)(−4Q)|
=
.
4π
0
d
2
π
0
d
2
3Q
2
|(−3Q)(−4Q)|
=
.
=
4π
0
d
2
π
0
d
2

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